Mohon dibantu penyelesaian ​

Jawaban:

x = coklat

y = kacang

z = nanas

2x + 2y + 2z = 4000 …… 1

3x + y + z = 4000 ……. 2

2x + 4y + z = 4500 …….. 3

eliminasi z di 1 dan 2

2x + 2y + 2z = 4000 |×1| 2x + 2y + 2z = 4000

3x + y + z = 4000 |×2| 6x + 2y + 2z = 8000

– 4x = -4000

x = 1000

eliminasi z di 2 dan 3

3x + y + z = 4000

2x + 4y + z = 4500

x – 3y = -500

1000 – 3y = -500

-3y = -1500

y = 500

3x + y + z = 4000

3×1000 + 500 + z = 4000

3000 + 500 + z = 4000

3500 + z = 4000

z = 500

model matematika

x = 1000, y = 500 , z = 500

harga setiap kue

kue coklat Rp 1000

kue kacang Rp. 500

kue nanas = Rp. 500

semoga membantu…