Tentukan persamaan kuadrat baru yg akar2nya dua kali lipat dari x^2 – 5x + 4 = 0​

cari akarnya dulu yekan :v

2x² – 5x + 4 = 0

x = -b ± √b² + 4ac /2(a)

x = -(-5) ± √-5² + 4.2.4 / 2(2)

x = 5 ± √25 + 24 / 4

x = 5 ± √49 / 4

x = 5 ± 7 /4

x1 = 5+7/4 = 12/4 = 3

x2 = 5-7/4 = -2/4

akar akar 2x lipat

x1 = 3 x 2 = 6

x2 = -2/4 x 2 = -1

akar akar nya

x1 = 6 & x2 = -1

x² – (x1 + x2)x + x1.x2 = 0

x² – (6 + (-1))x + 6.(-1) = 0

x² – 5x + (-6) = 0

x² – 5x – 6 = 0