Diketahui A = 17, U = 1 dan K = 11, sehingga AKU = 187. Jika nilai kata BUKU = 77, OBAT = 714 dan KUNO = 165, nilai kata BATUK adalah

Posted on

hard nih.
yg bisa fiks encer​

Diketahui A = 17, U = 1 dan K = 11, sehingga AKU = 187. Jika nilai kata BUKU = 77, OBAT = 714 dan KUNO = 165, nilai kata BATUK adalah

Jawaban:

2.618

Penjelasan dengan langkah-langkah:

DIKETAHUI :

A = 17

U = 1

K = 11

AKU = 17 × 11 × 1 = 187

_____________

» PENYELESAIAN SOAL

BUKU = B × 1 × 11 × 1= 77

B = 77 ÷ ( 11 )

B = 7

OBAT = 0 × 7 × 17 × T =714

OT = 714 ÷ ( 7 × 17 )

OT = 6

KUNO = 11 × 1 × N × 0 = 165

NO = 165 ÷ 11

NO = 15

OT ÷ NO = 6 ÷ 15

T ÷ N = 6 ÷ 15

T ÷ N = 2 ÷ 5

T = 2

N = 5

MAKA,

BATUK

= 7 × 17 × 2 × 1 × 11

= 2.618

Nilai kata BATUK adalah 2.618.

PENYELESAIAN

BUKU = 77

B × U × K × U = 77

B × 1 × 11 × 1 = 77

B × 11 = 77

B = sf frac {77}{11}

B = 7

.

OBAT = 714

O × B × A × T = 714

O × 7 × 17 × T = 714

O × 119 × T = 714

O × T = sf frac {714}{119}

O × T = 6

.

KUNO = 165

K × U × N × O = 165

11 × 1 × N × O = 165

11 × N × O = 165

N × O = sf frac {165}{11}

N × O = 15

sf frac{O times T}{N times O} = frac{6}{15}

sf frac{T}{N} = frac{2}{5}

T = 2

N = 5

BATUK

= B × A × T × U × K

= 7 × 17 × 2 × 1 × 11

= 119 × 2 × 11

= 238 × 11

= 2. 618