Carilah solusi dari persamaan kuadrat berikut :

1) 2x² – 6x + 9  = 0
x² – 3x = -9/2
(x – 3/2)² = -9/2 + 9/4 = -9/4
x – 3/2 = √(9/4) √(-1) …..(√(-1)= i
x – 3/2 = +_ 3/2  i
x = 3/2 + 3/2 i = 3/2 ( 1 + i)
x = 3/2 – 3/2 i = 3/2  ( 1 – i)

2)
6x² -2x + 3= 0
x² – 1/3 x = – 1/2
(x- 1/6)² = -1/2 +1/36 = - 17/36 = 17/36  (-1)
x – 1/6 = +_ 1/6 √(17(-1) ….(i =√(-1))
x = 1/6 + 1/6 i√17= 1/6 ( 1 + i√17)
x = 1/6 – 1/6 i√17 = 1/6 (1 – i√17)

3) 3x² -6x + 5= 0
x² – 2x = – 5/3
(x – 1)² = -5/3 + 1 = – 2/3
(x-1) = +_ √(2/3) (-1) =  +_ i√(2/3) = +_1/3 i √6

x = 1 + 1/3 i√6 = 1/3 ( 3 +i √6)
x = 1 – 1/3 i√6 = 1/3 (3 – i√6)