Titik balik minimum dari fungsi f(x) = Titik titik balik minimum dari fungsi f(x) = 8+3x²-3x³

By Admin ReiPosted on December 9, 2022

Titik balik minimum dari fungsi f(x) = Titik titik balik minimum dari fungsi f(x) = 8+3x²-3x³

F'(x)=0
$0 + 6x - 9 {x}^{2} = 0 \ 2x - 3 {x}^{2} = 0 \ x(2 - 3x) = 0 \ x1 = 0 \ 2 - 3x2 = 0 \ x2 = frac{2}{3} \$
f(0)=8+0-0=8
$f( frac{2}{3} ) = 8 + 3( frac{2}{3} {)}^{2} - 3( frac{2}{3} {)}^{3} \ f( frac{2}{3} )= frac{72 + 12 - 8}{9} = frac{76}{9} =8 frac{4}{9}$
titik balik minimum (0,8)