Kuis [+50]: - Universityku

Diketahui turunan ketiga fungsi f(x) adalah f'''(x) = 96x+30.
Jika f''(3) = 498, f'(7) = 6064 dan f(5) = 2862, tentukan rumus f(x).
[ngasal, hapus]

Kuis [+50]:

Jawaban:

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Penjelasan dengan langkah-langkah:

${f}^{111} (x) = 96x + 30 \ {f}^{11} (x) = 48 {x}^{2} + 30x + y \ {f}^{11} (3) = 48(9) + 30(3) + y \ 498 = 432 + 90 + y \ y = - 24 \ {f}^{11} (x) = 48 {x}^{2} + 30x - 24 \ {f}^{1} (x) = 16 {x}^{3} + 15 {x}^{2} - 24x + z \ {f}^{1} (7) = 16(343) + 15(49) - 24(7) \ + z \ 6064 = 5488 + 735 - 168 + z \ z = 9$

${f}^{1} (x) = 16 {x}^{3 } + 15 {x}^{2} - 24x + 9 \ f(x) = 4 {x}^{4} + 5 {x}^{3} - 12 {x}^{2} \ + 9x + w \ f(5) = 4(625) + 5(125) - 12(25) \ + 9(5) + w \ 2862 = 2500 + 625 - 300 + 45 + w \ w = - 8 \ f(x) = 4 {x}^{4} + 5 {x}^{3} - 12 {x}^{2} \ + 9x - 8$

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Detail Jawaban :

Mata Pelajaran : Matematika Dasar

Kelas : Kelas 11

Kunci : Turunan Fungsi

Kode : 11.2.1

Answered by : pushrank21