Quiss

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1. Berapa luas permukaan balok jika panjangnya 10 cm lebar 5 cm dan tinggi 6 cm

2. 5³ + 6²​

Quiss

Jawaban:

Lp = 2 . (pl + pt + lt)

Lp = 2 . (10×5 + 10×6 + 5×6)

Lp = 2 . (50 + 60 + 30)

Lp = 2 . 140

Lp = 280 cm²

..

5³ + 6²

= (5 × 5 × 5) + (6 × 6)

= 125 + 36

= 161

Jawaban:

1.) Lp = 2 × {( pl) + (p × t) + (1 × t)}

= 2 × {(10 cm x 6 cm) + (10 cm x 5 cm) + (6 cm x 5 cm)}

= 2 × (60 cm² + 50 cm² + 30 cm²)

= 2 x 140 cm²

= 280 cm²

2.)5³ + 6²

=125 + 36

=161