Mohon bantuannya kak yg pinter kimiaa tolong plisss​

Jawaban:

PH = -log [H3O+]

2,85 = -log [H3O+]

[H3O+] = 10^(-2,85)

pOH = 14-pH = 14 – 2,85 = 11,15

pOH = -log[OH-]

11,15 = -log[OH-]

[OH-] = 10^(-11,15)

Penjelasan:

maaf kalo salah