Tolong di jawab sama caranya kalo bisa caranya di poto makasihh

Y ² = 2 – x
x = 2 – y²
x² = (2 – y²)² = 4 – 2y² + y⁴
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∫ (x + x²) dy  {0….1}
= ∫ (2 – y² + 4 – 4y² + y⁴) dy  {0…..1}
= ∫ (6 – 5y² + y⁴) dy  {0…..1}
= 6y – 5y³/3 + y⁵/5  {1…..0}
= 6(1) – 5(1)³/3 + (1)⁵/5 – 0
= 6 – 5/3 + 1/5
= 6 – 25/15 + 3/15
= 6 - 22/15
= 90/15 – 22/15
= 68/15

∫ x dy  {-1….1}
= ∫ (2 – y²) dy {-1….1}
= 2y – y³/3 {1….-1}
= 2(1) – (1)³/3 – 2(-1) + (-1)³/3
= 2 – 1/3 + 2 – 1/3
= 4 – 2/3
= 12/3 – 2/3
= 10/3

Jawab
y² = 2 – x
x = 2  – y²

a)
₋₁¹∫ x dy =  ₋₁¹ ∫(2 -y²) dy 
= [ 2x – 1/3 y³]¹₋₁
= 2(2) -1/3(2)
=  10/3

b)
₀¹∫ (x + x²) dy  = ₀¹∫ (2-y²) +(2-y²)² dy
= ₀¹∫ 2 -y² + 4 – 4y² +y⁴  dy
= ₀¹∫ y⁴  – 5y² +6  dy
= 1/5 y⁵  -5/3 y³ + 6 y]¹₀
= 1/5 (1) – 5/3(1) + 6(1)
= 68/15