Kak tolong dibantu jawab ya dengan caranya juga no 1 dan 2

Kak tolong dibantu jawab ya dengan caranya juga no 1 dan 2

Jawaban:

$1. : frac{2}{5x} + frac{1}{4x} = \ frac{8 + 5}{20x} = frac{13}{20x} \ \ 2. : frac{3x}{7 {x}^{2} } + frac{2}{2x} = \ frac{6x + 14x}{14 {x}^{2} } = \ frac{20x}{14 {x}^{2} } = frac{10}{7x}$

maaf kalo salah

Penjelasan dengan langkah-langkah:

$\ begin{aligned}dfrac{2}{5x} + dfrac{1}{4x} &= dfrac{2(4x)}{(5x)(4x)}+ dfrac{(1)(5x)}{(4x)(5x)}\ &=dfrac{8x}{20x^2} +dfrac{5x}{20x^2}\ &= dfrac{8x+5x}{20x^2}\ &=dfrac{13x}{20x^2}end{aligned}$

$begin{aligned} frac{3x}{ {7x}^{2} } + dfrac{2}{2x} & = dfrac{(3x)(2x)}{(7 {x}^{2})(2x) } + dfrac{2( {7x}^{2}) }{ ({7x}^{2})(2) } \ &= dfrac{6 {x}^{2} }{14 {x}^{2} } + dfrac{14 {x}^{2} }{14 {x}^{2} } \ & = dfrac{6 {x}^{2} + 14 {x}^{2} }{14 {x}^{2} } \ &= frac{20 {x}^{2} }{14 {x}^{2} } \& = frac{10}{7} \ &= 1 frac{3}{7} end{aligned}$