[+50](10/10)

integral tentu

y = 2x, y = x²

2x = x²

-x² + 2x = 0

x² – 2x = 0

x(x – 2) = 0

x = 0 atau x = 2

cari volume benda putarnya :

batas atas 2 dan batas bawah 0

V = π∫ [f(x))² – g(x))² ]dx

V = π∫ [(2x)² – (x²)²]dx

V = π∫ [4x² – x⁴]dx

V = π∫ [4/3x³ – ⅕x⁵]dx

batas atas 2 dan batas bawah 0

V = π [4/3(2)³ – ⅕(2)⁵ – 4/3(0)³ – ⅕(0)⁵]

V = π [32/3 – 32/5 – 0]

V = 64/15π satuan volume