LAST QUIZ - Universityku

$huge sf int(x - 3)(x + 2)dx$
Yang jawab pakai latex wajib pakai huge semua ya di latexnya ^—^

LAST QUIZ

Penjelasan dengan langkah-langkah:

$huge sf int(x - 3)(x + 2)dx$

nilai (x – 3)(x + 2)

= x(x + 2)-3(x + 2)

= x² + 2x – 3x – 6

= x² – x – 6

$huge sfint {x}^{2} - x - 6 ~~~ dx$

$huge sf = frac{ {x}^{2 + 1} }{2 + 1} - frac{ {x}^{1 + 1} }{1 + 1} - 6x + c$

$huge sf = frac{ {x}^{3} }{3} - frac{ {x}^{2} }{2} - 6x + c$

$huge sf = frac{{x^3}}{3} -frac{ {x}^{2} }{2} - 6x + c$

Jawaban:

$hugedisplaystylesfint(x - 3)(x + 2)dx$

$hugedisplaystylesfint({x}^{1 + 1} + 2x - 3x - 3 cdot 2)dx$

$hugedisplaystylesfint({x}^{2} - x - 6)$

$hugesf=frac{{x}^{2 + 1} }{2 + 1} - frac{{x}^{1 + 1}}{1 + 1} - 6x + C$

$hugesf=frac{{x}^{3}}{3} - frac{{x}^{2}}{2} - 6x + C$