Tolong bantu tugas ku no 2

Tolong bantu tugas ku no 2

Jawaban Terkonfirmasi

$2A+B=2left[begin{array}{cc}3&4\a-b&2end{array}right] + left[begin{array}{cc}2a&6\-1&cend{array}right] \ left[begin{array}{cc}a+3&7b\-11&8end{array}right] = left[begin{array}{cc}6&8\2(a-b)&4end{array}right] + left[begin{array}{cc}2a&6\-1&cend{array}right] \ left[begin{array}{cc}a+3&7b\-11&8end{array}right]= left[begin{array}{cc}6+2a&14\2a-2b-1&4+cend{array}right] \7b=14\b=2\4+c=8\c=4\a+3=6+2a\a=-3$

Jadi,

$A=left[begin{array}{cc}3&4\-3-2&2end{array}right] \ = left[begin{array}{cc}3&4\-5&2end{array}right]$

$A^T= left[begin{array}{cc}3&-5\4&2end{array}right] \ A^T+2B-C\= left[begin{array}{cc}3&-5\4&2end{array}right]+2 left[begin{array}{cc}-6&6\-1&4end{array}right]- left[begin{array}{cc}-1&4\2&6end{array}right] \= left[begin{array}{cc}3&-5\4&2end{array}right]+ left[begin{array}{cc}-12&12\-2&8end{array}right]- left[begin{array}{cc}-1&4\2&6end{array}right] \= left[begin{array}{cc}3-12+1&-5+12-4\4-2-2&2+8-6end{array}right] \= left[begin{array}{cc}-8&3\0&4end{array}right]$

Semangat!