Tentukan persamaan garis yang melalui titik (5,0) dan (0,-3)

Jawab :

m = y2 – y1/ x2 – x1 = (-3) – 0/ 0 – 5 = -3/-5 = 3/5

y – y1 = m(x – x1)
y – 0 = 3/5(x – 5)
y – 0 = 3/5x – 3/5 . 5
y – 0 = 3/5x – 15/5
_________________ x 5
5 . y – 0 . 5 = 3/5x . 5 – 15/5 . 5

5y – 0 = 3x – 15
5y – 0 – 3x + 15 = 0
5y – 3x + 15 = 0
-3x + 5y + 15 = 0