Jika panjang AC = 8 cm dan AB = 15 cm, panjang BC adalah?

Jika panjang AC = 8 cm dan AB = 15 cm, panjang BC adalah?

Jawaban:

AC = 8 cm

AB = 15 cm

BE = ?

tentukan panjang BC

${bc}^{2} = {ac}^{2} + {ab}^{2} \ {bc}^{2} = {8}^{2} + {15}^{2} \ {bc}^{2} = 64 + 225 \ {bc}^{2} = 289 \ bc = sqrt{289} \ bc = 17$

segitiga ADC = segitiga EDC

maka AC = EC = 8

BC = BE + EC

17 = BE + 8

BE = 17 – 8

BE = 9

Jawaban :

bc² = ab²+ac²

bc² = 15²+8²

bc² = 225+64

bc² = 289

bc= √289

bc = 17

maaf kalau salah….

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