Jika massa Jenis air (P air = 1000 kg /m3), massa benda = 20KG,

V tercelup = 2/3 V total,
berapakah massa benda (P benda)? (9= 10 m/s2).

mohon dijawab bapa ibu atau teman teman sekalian

Jika massa Jenis air (P air = 1000 kg /m3), massa benda = 20KG,

Jawaban:

$rho : text{benda} : = 666.67 : kg/ {m}^{3}$

Penjelasan:

$rho(f).v(f) = rho(b).v(b) \ 1000 times frac{2}{3} v(b) = rho(b) times v(b) \ frac{2000}{3} = rho(b) \ rho(b) = 666.67 : kg. {m}^{ - 3}$