Jika Sr (OH)² dianggap terionisasi sempurna, maka pH larutan 4 liter 0,025 M adalah​

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Jika Sr (OH)² dianggap terionisasi sempurna, maka pH larutan 4 liter 0,025 M adalah​

Jawaban:

pH = 12 + log 5

Penjelasan:

Sr(OH)2 => Sr^2+ + 2 OH^-

valensi basa ( b ) = 2

[OH-] = b. Mb

=> 2 . 0,025

=> 0,05 M ~ 5×10^-2 M

pOH = – log [OH-]

pOH = 2 – log 5

pH = 14 – pOH

pH = 14 – ( 2 – log 5 )

pH = 12 + log 5