Kak mohon bantuannya ​

P = e.A.σ.T⁴

T = (P/e.A.σ)'1/4

= (7π²/8.2π × 10-⁴.567 × 10'-10)'1/4

= (2198 × 10¹²/9072)'1/4

= ⁴√(0,242 × 10¹²)

= 701 °K ✓✓