hitunglah molaritas larutan 3 liter larutan yang mengandung 6 gram CH3COOH (Dik.Ar: C = 12,0=16 dan H=1)​

Jawaban:

M = m/Mr x 1000/V

M = 6 gram / 60 x 1000/3000 ml

M = 0.0334 mol/L

Penjelasan:

M = m/Mr x 1000/ V

M= Molaritas

m = massa (gram)

Mr = Massa molekul relatif

V = Volume (ml)

Mr CH3COOH = C (12 x 2) + H (1 x 4) + O (16 x 2) = 60

V = 3 L = 3000 mL