Q. @Kuc1ntaKamu1) 6d + 2k – 2(6)Jika : d = 10 k = 3​

Pendahuluan

Operasi hitung bilangan bulat adalah operasi hitung yang dilakukan terhadap bilangan bulat. Berikut ini operasi hitung yang dapat dilakukan pada bilangan bulat :

Pertambahan

Pertambahan sering ditandai dengan tanda “+”

Contoh pertambahan 1 :

1 + 1 = 2

2 + 1 = 3

3 + 1 = 4

4 + 1 = 5

5 + 1 = 6

6 + 1 = 7

7 + 1 = 8

8 + 1 = 9

9 + 1 = 10

10 + 1 = 11

Contoh pertambahan 2 :

1 + 2 = 3

2 + 2 = 4

3 + 2 = 5

4 + 2 = 6

5 + 2 = 7

6 + 2 = 8

7 + 2 = 9

8 + 2 = 10

9 + 2 = 11

10 + 2 = 12

Contoh pertambahan 3 :

1 + 3 = 4

2 + 3 = 5

3 + 3 = 6

4 + 3 = 7

5 + 3 = 8

6 + 3 = 9

7 + 3 = 10

8 + 3 = 11

9 + 3 = 12

10 + 3 = 13

Pengurangan

Pengurangan sering ditandai dengan tanda “-”

Contoh pengurangan 1 :

1 – 1 = 0

2 – 1 = 1

3 – 1 = 2

4 – 1 = 3

5 – 1 = 4

6 – 1 = 5

7 – 1 = 6

8 – 1 = 7

9 – 1 = 8

10 – 1 = 9

Contoh pengurangan 2 :

1 – 2 = -1

2 – 2 = 0

3 – 2 = 1

4 – 2 = 2

5 – 2 = 3

6 – 2 = 4

7 – 2 = 5

8 – 2 = 6

9 – 2 = 7

10 – 2 = 8

Contoh pengurangan 3 :

1 – 3 = -2

2 – 3 = -1

3 – 3 = 0

4 – 3 = 1

5 – 3 = 2

6 – 3 = 3

7 – 3 = 4

8 – 3 = 5

9 – 3 = 6

10 – 3 = 7

Perkalian

Perkalian sering ditandai dengan tanda “×”

Contoh perkalian 1 :

1 × 1 = 1

2 × 1 = 2

3 × 1 = 3

4 × 1 = 4

5 × 1 = 5

6 × 1 = 6

7 × 1 = 7

8 × 1 = 8

9 × 1 = 9

10 × 1 = 10

Contoh perkalian 2 :

1 × 2 = 2

2 × 2 = 4

3 × 2 = 6

4 × 2 = 8

5 × 2 = 10

6 × 2 = 12

7 × 2 = 14

8 × 2 = 16

9 × 2 = 18

10 × 2 = 20

Contoh perkalian 3 :

1 × 3 = 3

2 × 3 = 6

3 × 3 = 9

4 × 3 = 12

5 × 3 = 15

6 × 3 = 18

7 × 3 = 21

8 × 3 = 24

9 × 3 = 27

10 × 3 = 30

Pembagian

Pembagian sering ditandai dengan tanda “÷”

Contoh pembagian 1 :

1 ÷ 1 = 1

2 ÷ 1 = 2

3 ÷ 1 = 3

4 ÷ 1 = 4

5 ÷ 1 = 5

6 ÷ 1 = 6

7 ÷ 1 = 7

8 ÷ 1 = 8

9 ÷ 1 = 9

10 ÷ 1 = 10

Contoh pembagian 2 :

2 ÷ 2 = 1

4 ÷ 2 = 2

6 ÷ 2 = 3

8 ÷ 2 = 4

10 ÷ 2 = 5

12 ÷ 2 = 6

14 ÷ 2 = 7

16 ÷ 2 = 8

18 ÷ 2 = 9

20 ÷ 2 = 10

Contoh pembagian 3 :

3 ÷ 3 = 1

6 ÷ 3 = 2

9 ÷ 3 = 3

12 ÷ 3 = 4

15 ÷ 3 = 5

18 ÷ 3 = 6

21 ÷ 3 = 7

24 ÷ 3 = 8

27 ÷ 3 = 9

30 ÷ 3 = 30

Pembahasan

Jika :

d = 10

k = 3

Maka tentukan :

6d + 2k – 2(6) = ??

Jawab :

6d + 2k – 2(6)

= 6(10) + 2(3) – 2(6)

= (6 × 10) + (2 × 3) – (2 × 6)

= 60 + 6 – 12

= 66 – 12

= 54

cara terlampir

Kesimpulan

Jadi, hasil dari 6d + 2k – 2(6) adalah 54

Pelajari Lebih Lanjut

• brainly.co.id/tugas/396532 (Perkalian 1 Sampai 10)
• brainly.co.id/tugas/462369 (Pengertian Penjumlahan Dan Pengurangan)
• brainly.co.id/tugas/6659367 (Pengertian Perkalian Dan Pembagian)

Detail Jawaban

• Mapel : Matematika
• Kelas : 5
• Tingkat : SD
• Materi : Operasi hitung bilangan bulat
• Bab : 1
• Kode soal : 2
• Kode Kategorisasi : 5.2.1
• Kata kunci : Operasi hitung bilangan bulat

Jawaban:

Jika :

d = 10

k = 3

6d + 2k – 2(6)

PENYELESAIAN

6d + 2k – 2(6)

= 610 + 23 – (2 × 6)

= 610 + 23 – 12

= 633 – 12

= 621

atau :

6d + 2k – 2(6)

= 6(10) + 2(3) – 2(6)

= (6 × 10) + (2 × 3) – (2 × 6)

= 60 + 6 – 12

= 66 – 12

= 54