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3. v = π × r² × t

v = 22/7 × 10 cm × 10 cm × 21 cm

v = 22 × 100 cm² × 3 cm

v = 2.200 cm² × 3 cm

v = 6.600 cm³

4. sisa = 4/5 nya

yang bocor = 1 – 4/5 = 5/5 – 4/5 = 1/5 bagian

maka, volume minyak yg bocor :

= 1/5 × π × r² × t

= 1/5 × 22/7 × (2 ÷ 2)² × 1,4

= 1/5 × 22 × 1 m × 1 m × 1,4 m

= 1/5 × 22 × 1,4 m³

= 1/5 × 30,8 m³

= 6,16 m³

= (6,16 × 1000) liter

= 6.160 liter