Please jawab y!!!!besok dikumpul

Please jawab y!!!!besok dikumpul

Jawaban:

1.b

$frac{2 {a}^{ - 1} {b}^{ - 2} }{ {c}^{ - 3} } = \ frac{ frac{1}{2a} {b}^{2} }{ frac{1}{ {c}^{3} } } = \ frac{ frac{ {b}^{2} }{2a} }{ frac{1}{ {c}^{3} } } = \ frac{ {b}^{2} }{2a} times frac{ {c}^{3} }{1} = \ frac{ {b}^{2} {c}^{3} }{2a}$

1.c

$frac{ {6x }^{ - 3} }{ {3xy}^{ - 1} {z}^{ - 2} } = \ frac{ frac{1}{ {6x}^{3} } }{3x frac{1}{y} frac{1}{z} } = \ frac{ frac{1}{ {6x}^{3} } }{ frac{3x}{yz} } = \ frac{1}{ {6x}^{3} } times frac{yz}{3x} = \ frac{yz}{18 {x}^{4} }$

2.a

$sqrt[5]{8} = sqrt[5]{ {2}^{3} } = {2}^{ frac{3}{5} }$

2.c

$sqrt[4]{ frac{1}{4} } = sqrt[4]{ frac{1}{ {2}^{2} } } = sqrt[4]{ {2}^{ - 2} } = {2}^{ frac{ - 2}{4} } = {2}^{ frac{1}{2} }$

3.a

${2}^{ frac{3}{4} } = sqrt[3]{ {2}^{4} } = sqrt[3]{16}$

3.b

${( frac{1}{2}) }^{ - frac{2}{3} } = \ frac{1}{ {( frac{1}{2}) }^{ frac{2}{3} } } = \ frac{1}{ sqrt[3]{ {( frac{1}{2} )}^{2} } } = \ frac{1}{ sqrt[3]{ frac{1}{4} } }$

4.a

$sqrt[5]{ {32}^{2} } = \ ({32})^{ frac{2}{5} } = \ {(16 times 2})^{ frac{2}{5} } = \ {16}^{ frac{2}{5} } times {2}^{ frac{2}{5} } = \ { {(2}^{4} )}^{ frac{2}{5} } times {2}^{ frac{2}{5} } = \ {2}^{ frac{8}{5} } times {2}^{ frac{2}{5} } = \ {2}^{ frac{8}{5} + frac{2}{5} } = \ {2}^{ frac{10}{5} } = \ {2}^{2} = \ 4$

4.c

$sqrt[4]{ {81}^{3} } = {81}^{ frac{3}{4} } = {( {3}^{4} )}^{ frac{3}{4} } = {3}^{ frac{12}{4} } = {3}^{3} = 9$

5.a

${36}^{ frac{2}{3} } = sqrt[3]{ {36}^{2} } = sqrt[3]{ {6}^{4} } = sqrt[3]{ {6}^{3} times 6} = 6 sqrt[3]{6}$

5.c

${9}^{ frac{3}{2} } = sqrt{ {9}^{3} } = sqrt{ {9}^{2} times 9 } = 9 sqrt{9}$

ini PR kan? Dikerjakan sendiri ya agar kamu paham. Aku hanya membantu sedikit agar kamu bisa pelajari dan pahami untuk soal lainnya. Sekalian aku tuliskan formula bilangan berpangkat, pecahan dan akar agar kamu semakin mudah memahami darimana semua angka ini datang. Selamat belajar

Gambar Jawaban