Tentukan akar akar dari persamaan :1) 2x²-6x=82) 6x²+7x-3=0

1)
2x² – 6x = 8
= 2x² – 6x – 8 = 0
= 2x² + 2x – 8x – 8
= (2x² + 2x) (- 8x – 8)
= 2x (x + 1) – 8(x + 1)
= (2x – 8) (x + 1)

2)
6x² + 7x – 3 = 0
= 6x² + 9x – 2x – 3
= (6x² + 9x) (- 2x – 3)
= 3x(2x + 3) – 1(2x + 3)
= (3x – 1) (2x + 3)

Maaf Kalau Salah