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The mass of a liquid is 2 kg the liquid is heated from 12°c to 52°c the head needed is 192 kl what is the specific head of the liquid???
Dik.
m = 2 kg
∆T = (52-12) °C= 40 °C
Q = 192 kJ = 192000 J
Dit. c = ?
Jawab;
Q = m.c.∆T
c = Q/(m.∆T)
c = 192000/(2.40)
c = 192000/80 = 2400 J/(kg.°C)