⁵log 125 – ³log 18 + ²log 16 – ³log ½ bantuin dong pliss
⁵log 125 – ³log 18 + ²log 16 – ³log ½
= ⁵log5³ – ³log(9×2) + ²log2⁴ – ³log2⁻¹
= 3 ⁵log5 -( ³log3² + ³log2) + 4 ²log2 – (-1) ³log2
= 3 x 1 – 2 x 1 – ³log2 + 4 x 1 + ³log2
= 3 – 2 + 4
= 5
⁵log 125 – ³log 18 + ²log 16 – ³log ½ bantuin dong pliss
⁵log 125 – ³log 18 + ²log 16 – ³log ½
= ⁵log5³ – ³log(9×2) + ²log2⁴ – ³log2⁻¹
= 3 ⁵log5 -( ³log3² + ³log2) + 4 ²log2 – (-1) ³log2
= 3 x 1 – 2 x 1 – ³log2 + 4 x 1 + ³log2
= 3 – 2 + 4
= 5