Jika 125 log 9 = a Maka 27 log 25 adalah … Pakai cara nya ya

125log9 = a
(5^3)log(3^2) = a
(2/3) 5log3 = a
5log3 = a . 3/2
5log3 = (3a)/2
3log5 = 2/(3a)

27log25 = (3^3)log(5^2)
= (2/3) 3log5
= (2/3) . 2/(3a)
= 4/(9a)

125 log 9 = a
9 log 125 = 1/a

9 log 125= 3^2 log 5^3
= 3/2 3log5=a
Sehingga jika 3log5= ax2/3

Maka 27 log 25 =3^3log5^2
=2/3 3log5
Ganti 3log5 =ax2/3
2/3xax2/3 =4/9 a
Jadi jwaban 4/9 a