Jika (fog)(x) = 2x + 1 dan g(x) = x - 2. Maka nilai f(3) =

Jika (fog)(x) = 2x + 1 dan g(x) = x – 2. Maka nilai f(3) =

$hugecolorbox{pink}{Ambiziuz02}$

_______________________________________________

${boxed{mathfrak{hugeblue{{boxed{mathfrak{hugered{Penyelesaian}}}}}}}}$

_______________________________________________

▪ $large (fog)(x) = f(g(x))$

▪ $large 2x + 1 = f(x - 2)$

▪ $large f(x - 2) = 2x + 1$

▪ $large f(5 - 2) = 2(5) + 1$

▪ $large f(3) = 10 + 1$

▪ $large red{f(3) = 11}$

$hugepurple{boxed{orange{boxed{red{f(3) = 11}}}}}$

_______________________________________________

$largebigstar$ Detail Jawaban $largebigstar$

▪ Mapel : Matematika

▪ Cabang : –

▪ Materi : Fungsi Komposisi

▪ Kelas/Jenjang : 10 SMA

▪ Kata Kunci : Komposisi Fungsi

_______________________________________________

Jawaban:

fog(x) = 2x + 1

g(x) = x – 2

f(g(x)) = 2x + 1

f(x – 2) = 2x + 1

Mis :

x – 2 = a

x = a + 2

Maka ,

f(a) = 2(a + 2) + 1

f(a) = 2a + 5

f(x) = 2x + 5

f(3) = 2(3) + 5 = 11