Segitiga ABC siku siku di B. Panjang AC = 4 akar 6 dan Mohon bantuannya ya ^^

BC = 12 cm
∠A = 60°
∠C = 90° – 60° = 30°
sin ∠A = sin 60° = 1/2 √3 = cos ∠A = cos 30°.
sin ∠C = sin 30° = 1/2 = cos ∠C = cos 60°.
sin 60° = BC/AC
⇔ 1/2 √3 = 12/AC
⇔ AC = 12/(1/2 √3)
⇔ AC = 12/(√3/2)
⇔ AC = (12 x 2)/√3
⇔ AC = (24/√3) x (√3/√3)
⇔ AC = (24/3 √3)
⇔ AC = 8√3

Semoga membantu