^2 x + 3 log (^x2-3x+2)= 2 x + 3 log (5 x -8) ​

x² – 3x + 2 = 5x – 8

x² – 8x + 10 = 0

x1,2 = (-b ± √(b² – 4ac))/2a

= (8 ± √(8² – 4(1)(10)))/2

= (8 ± 2√6)/2

= 4 ± √6

Syarat:

• 2x + 3 > 0

2x > -3

x > -3/2

x > -1,5

• 2x + 3 ≠ 1

2x ≠ -2

x ≠ -1

• x² – 3x + 2 > 0

(x – 2)(x – 1) > 0

x < 1 atau x > 2

• 5x – 8 > 0

5x > 8

x > 8/5

x > 1,6

Maka: HP = {x = 4 + √6}