Pertanyaan no 1 bang Basa lemah AL(Oh)3 0,1M dengan ka= 10-5 Tentukan pH larutan

Penjelasan:

Kw = [Ka][Kb]

10^-14 = 10^-5 [Kb]

[Kb] = 10^-14 / 10^-5

[Kb] = 10^-9

[OH-] = √(Kb . M)

= √(10^-9 x 10^-1)

= √10^-10

= 10^-5

pH = -log [OH-]

= -log 10^-5

= 5