Q. [ + 50 ] - Universityku

Q. [ + 50 ]

❐ Integral

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Integralkan

∫(12x² + 6x) dx

= 12x³/3 + 6x²/2 + c

= 4x³ + 3x² + c

Substitusi batas atas dan bawah

= (4(3)³ + 3(3)²) – (4(1)³ + 3(1)²)

= (4(27) + 27) – (4 + 3)

= (108 + 27) – 7

= 108 + 20

= 128

Jawab:
128 S.L.

Penjelasan dengan langkah-langkah:
$displaystylesf int _1^312x^2+6x:dx =\\left[frac{12}{2+1}x^{2+1}right]_1^3+left[frac{6}{1+1}x^{1+1}right]_1^3=\\left[frac{12}{3}cdot x^{3}right]_1^3+left[frac{6}{2}cdot x^{2}right]_1^3=\\left[4x^{3}right]_1^3+left[3x^{2}right]_1^3=$
(4(3³-1³)) + (3(3²-1²)) =
(4(27-1)) + (3(9-1)) =
(4(26)) + (3(8)) =
104 + 24 =
128 S.L.

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