F(x+1)=2x-3 g(x)=x2-2x-1 h(x)=1-x rumus (g0h0f)

F(x+1) = 2x-3
g(x) = x²-2x-1
h(x) = 1-x
(g o h o f) = g(h(f(x+1)))
= g(h(2(x+1)-3))
= g(h(2x+2-3))
= g(h(2x-1))
= g(1-(2x-1))
= g(1-2x-1)
= g(-2x)
= (-2)²-2(-2)-1
= 4+4-1
= 7