Bantu dong yang di lingkerin doang​

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Bantu dong yang di lingkerin doang​

Bantu dong yang di lingkerin doang​

Jawab:

b. (5x²y⁴) (2xy³) = 5 . 2 . x²⁺¹ . y⁴⁺³

                          = 10x³y⁷

d. (frac{5}{3})^3 = frac{5 times 5 times 5}{3 times 3 times 3} = frac{125}{27}

f. (7p³q²)² = 7 . p³ˣ² . q²ˣ²

                = 7p⁶q⁴

h. frac{2}{p^{-4}} = 2p^4

n. (4a)^{-2} =frac{1}{(4a)^2} = frac{1}{16a^2}

Penjelasan dengan langkah-langkah:

b.

(5x {}^{2} y {}^{4} )(2xy {}^{3} ) = 5 times 2((x {}^{2} times x)(y {}^{4} times y {}^{3} )) \ = 10(x {}^{3} y {}^{7} ) \ = 10x {}^{3} y {}^{7}

d.

(frac{5}{3})^3=frac{5^3}{3^3}=frac{125}{27}= 4frac{17}{27}

f.

(7p {}^{3} q {}^{2} ) {}^{2} = 7 {}^{2} times p {}^{3 times 2} q {}^{2 times 2} \ = 49p {}^{6} q {}^{4}

h.

frac{2}{p {}^{ - 4} } = frac{2}{ frac{1}{p {}^{4} } } \ = 2 times frac{p {}^{4} }{1} \ = 2p {}^{4}

n.

(4a) {}^{ - 2} = frac{1}{(4a) {}^{2} } \ = frac{1}{4 {}^{2} a {}^{2} {} } \ = frac{1}{16a {}^{2} }