Tlng bntu yg dilingkari dong, pliss bgt,

Tlng bntu yg dilingkari dong, pliss bgt,

Jawaban Terkonfirmasi

7b.
${36}^{x + 5} = ({ frac{1}{216} })^{x - 1}$
$( {6}^{2})^{x + 5} = ({ {6}^{ - 3} })^{x - 1}$
${6}^{2x + 10} = {6}^{ - 3x + 3}$
$2x + 10 = - 3x + 3$
$2x + 3x = 3 - 10$
$5x = - 7$
$x = - frac{7}{5}$
8a.
$sqrt[x - 1]{64} = sqrt[2x + 3]{8}$
$sqrt[x - 1]{ {2}^{6} } = sqrt[2x + 3]{ {2}^{3} }$
${2}^{ frac{6}{x - 1} } = {2}^{ frac{3}{2x + 3} }$
$frac{6}{x - 1} = frac{3}{2x + 3}$
$6(2x + 3) = 3(x - 1)$
$12x + 18 = 3x - 3$
$12x - 3x = - 3 - 18$
$9x = - 21$
$x = - frac{21}{9} = - frac{7}{3}$
9a.
${7}^{x + 5} = {2}^{x + 5}$
$^{x + 5} log(7) = ^{x + 5}log(2)$

nanti lagi dilanjutkannya . mohon maaf