Tolong ya teman - teman

Tolong ya teman – teman

Jawaban Terkonfirmasi

2(x-3) < 3(x+1) (cek apakah soalnya seperti ini?)
⇔2x-6 < 3x+3
⇔2x-3x < 3+6
⇔-x < 9
⇔x > -9

12-6y ≥ -6
⇔-6y ≥ -6-12
⇔-6y ≥ -18
⇔-y ≥ -3
⇔y ≤ 3

$frac{6x-3}{3} geq frac{2(x+3)}{2}\2x-1 geq x+3\2x-x geq 3+1\x geq 4$

$frac{1}{3}x+1 geq frac{1}{2}(x-1)\ frac{1}{3}x+1 geq frac{1}{2}x- frac{1}{2}\ frac{1}{3}x- frac{1}{2}x geq - frac{1}{2}-1\ frac{2x-3x}{6} geq -frac{1}{2}- frac{2}{2}\ -frac{x}{6} geq - frac{3}{2}\ -frac{x}{6} geq - frac{9}{6}\x leq 9$

Semangat!