Tolong dijawab secepatnya please!!​

1. a. Titik (2,-1) dan (-4,-2)

x1 = 2

x2 = -4

y1 = -1

y2 = -2

Gradien (m) = ∆y/∆x => y2-y1/x2-x1

<=> -2-(-1)/-4-2

<=> -2+1/-6

<=> -1/6

b. Titik (0,3) dan (5,4)

x1 = 0

x2 = 5

y1 = 3

y2 = 4

Gradien (m) = ∆y/∆x => y2-y1/x2-x1

<=> 4-3 / 5-0

<=> 1/5

2. a. Titik (1,3) dan (3,9)

x1 = 1

x2 = 3

y1 = 3

y2 = 9

Gradien (m) = ∆y/∆x => y2-y1/x2-x1

<=> 9-3/3-1

<=> 6/2

<=> 3

b. Titik (5, 3) dan (0, 3)

x1 = 5

x2 = 0

y1 = 3

y2 = 3

Gradien (m) = ∆y/∆x => y2-y1/x2-x1

<=> 3-3/0-5

<=> 0/-5

<=> 0

c. Titik (3, 2) dan (3, 0)

x1 = 3

x2 = 3

y1 = 2

y2 = 0

Gradien (m) = ∆y/∆x => y2-y1/x2-x1

<=> 0-2/3-3

<=> -2/0

<=> Tidak terdefinisi

3. Persamaan 5x + 10y + 3 = 0

Gradien (m) = -a/b

a = koefisien x = 5

b = koefisien y = 10

m = -5/10 = -½

b. Persamaan -12x + 3y = 7 bisa diubah menjadi

-12x + 3y -7 = 0

Gradien (m) = -a/b

a = koefisien x = -12

b = koefisien y = 3

m = -(-12) /3

= 12/3 = 4

Maaf kalo salah