Mohon bantuannya kak,no 4 dan 5

4) 6x² – 5x + 1 = 0
(3x – 1)(2x – 1) = 0
3x – 1 = 0
3x = 1
→ x1 = ⅓

2x – 1 = 0
2x = 1
→ x2 = ½

hp = { ⅓ , ½ }
jawaban : C

5) 3x² + 2x – 4 = 0
D = b² – 4ac
D = 2² – 4(3)(-4)
D = 4 + 48
D = 52
√D = √52 = 2√13

x1,2 = ( -b ± √D )/2a
x1,2 = ( -2 ± 2√13)/(2.3)
x1,2 = ( -2 ± 2√13)/6
x1,2 = ⅓( – 1 ± √13 )

(x1 – x2)²
= [ ( -1 + √13 )/3 – ( -1 -√13)/3 ]²
= [ ( -1+1 + √13+√13)/3 ]²
= [ (2√13)/3 ]²
= ( 2²x13)/3²
= 52/9
jawaban : D