Soal ada di gambar, minta penjelasan. terimakasih
cari momen inersia bola pejalnya dulu..
r = 20 cm = 2 x 10^-1 m
kec sudut (w) =
750 rpm = 750 x 2π/60 rad/s = 25 π rad/s
momen inersia ya =
I = 2/5 x m x r² = 2/5 x 0,25 x (2x 10^-1)² = 0,1 x 4 x 10^-2 kg m² = 4 x 10^-3 kg m²
momentum sudut =
L = I x w
L = 4 x 10^-3 x 25 π
L = 100 π x 10^-3
L = 100/1000 π
L = 0,1 π kg m²/s
Penjelasan:
Momentum Sudut
L = Iw
I = momen inersia bola pejal (2/5mr^2)
w = kecepatan sudut (rad/s)
w = 750 rpm
= 750 rotasi/menit × 2pi rad/rotasi × 1 menit/60 sekon
= 750×2pi/60
= 25 pi rad/s
L = 2/5mr^2×w
= 2/5×0,25×(0,2^2)×25pi
= 0,4×0,25×0,04×25pi
= 0,1 pi kg m^2/s