Q last ._ - Universityku

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$sf : hasil : dari : int(2x - 1) {( {x}^{2} - x + 3) }^{3} : dx : adalah : ..$
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$sf a) : frac{1}{3} {( {x}^{2} - x + 3)}^{3} + C$
$sf : b) : frac{1}{4} {( {x}^{2} - x + 3)}^{3} + C$
$sf : c) : frac{1}{4} {( {x}^{2} - x + 3)}^{4} + C$
$sf : d) : frac{1}{2} {( {x}^{2} - x + 3)}^{4} + C$
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RULES :
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》Pake Cara.
》No NGASAL.
》No copas.
》No bhs elien ( jfjsjs )
》RAPI.
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Q last ._

Jawab:
¹/₄(x²-x+3)⁴ + C [C]

Penjelasan dengan langkah-langkah:
∫(2x-1)(x²-x+3)³ dx =
u = x²-x+3
du = (x²-x+3)'dx
du = (2x²⁻¹-1x¹⁻¹+0) dx
du = 2x-1 dx
dx = (1/(2x-1))du
∫(2x-1)(x²-x+3)³ dx =
∫(2x-1)(u)³ (1/(2x-1))du =
∫(2x-1)/(2x-1) u³ du =
∫u³du
¹/₃₊₁u³⁺¹ + C =
¹/₄u⁴ + C =
u = x²-x+3, maka
¹/₄(x²-x+3)⁴ + C [C]

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