Diketahui ABCD aadalah sebuah segi empat. ABCD direfleksikan terhadap garis y= 2 sehingga diperoleh bayangan dengan titik A'(-5,-4), B`(2,-2), C’ (-4,-8), dan D'(2,-4). Tentukan koordinat A’B’C & D?????

Ksimpulan : x(a,b) → C y=h →x'(a,2h-b)
jd : A (a,b) → C y=2 → A' (-5, -4)
A (-5, b) → C y=2 → A' (-5, -4)
-4 =2h-b
-4 = 2.2-b
-4 – 4= 4 – 4 -b
-8 = -b
8 = b
B (a,b) → C y=2→ B' (2,-2)
B (2,b) → C y=2 → B'(2,-2)
-2 = 2.2 – b
-2 -4 = 4 – 4 -b
-6 = -b
6 = b
C (a,b) → C y=2 → C' (-4,-8)
C (-4,b) → C y=2 → C' (-4,-8)
-8 = 2.2 – b
-8 -4 = 4-4-b
-12= -b
12 = b
D (a,b) → C y=2 → D' (2,-4)
D (2,b) → C y=2 → D' (2,-4)
-4 = 2.2-b
-4 – 4= 4-4-b
-8 = -b
8 = b