Diketahui vektor a = (-3,4) b = (1,1) tentukan |a|+|b|

Diketahui vektor a = (-3,4) b = (1,1) tentukan |a|+|b|

Jawab:

$5 + sqrt{2}$

Penjelasan dengan langkah-langkah:

Diketahui:

$a = left(begin{array}{ccc}-3\4end{array}right)$

$b = left(begin{array}{ccc}1\1end{array}right)$

Ditanya:

$|a| + |b|$

Rumus besaran vektor:

$| a | = sqrt{i^2+ j^2 } \|a| = sqrt{x^2 + y^2}$

Maka,

$a = left(begin{array}{ccc}-3\4end{array}right)$

$a = -3i + 4j$

$|a| = sqrt{-3^2 + 4^2}$

$|a| = sqrt{9 + 16}$

$|a| = sqrt{25}$

$|a| = 5$

$b = left(begin{array}{ccc}1\1end{array}right)$

$b = i + j$

$|b| = sqrt{1^2 + 1^2}$

$|b| = sqrt {1+1}$

$|b| = sqrt {2}$

$|a| + |b| = 5 + sqrt{2}$