³log(x²-6+x)=0, tentukan:a. x1 + x2b. x1 . x2c. x1² + x2²d. x1³ . x2³​

logaritma

³log (x² – 6 + x) = 0

x² – 6 + x = 1

x² + x – 7 = 0

x1 + x2 = -b/a = -1/1 = -1

x1.x2 = c/a = -7/1 = -7

x1² + x2²

= (x1 + x2)² – 2x1x2

= 1 – 2(-7)

= 15

x1³ + x2³

= (x1 + x2)(x1² + x2² + x1x2)

= -1(15 + (-7))

= -8