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Jawab:
Penjelasan dengan langkah-langkah:
komposisi fungsi
fog(x)= f { g(x)}
gof(x)= g{ f(x)}
__
soal
f(x)= 3x+ 1
g(x)= 1/ (x + 2)
a. gof(x) =
= g( f(x))
= 1/ { f(x) + 2}
= 1 / {3x+1 + 2 }
= 1/ { 3x + 3}
b. fof(x) =
= f{ f(x)}
= 3. f(x) + 1
= 3 (3x + 1) + 1
= 9x + 3 + 1
= 9x + 4