Tentukan pH dari: larutan Ca(OH)2 0,005M?

[OH] =2 x 0,005
=0,01 = 10^-2
poh=2
ph =12

Ca(OH)2 –> Ca^+ + 2OH^-
[OH^-] = 2 x 5 x 10^-3 = 10^-2
pOH = -log[OH^-] = -log10^-2= 2
pH = 14-2 = 12