F(x):2x+3 dan G(x):x2-4x-6 tentukan( F09)(x)

~Fungsi Komposisi

f(x) = 2x + 3

g(x) = x² – 4x – 6

Maka :

(f o g)(x) = 2(x² – 4x – 6) + 3

(f o g)(x) = 2x² – 8x – 12 + 3

(f o g)(x) = 2x² – 8x – 9

(g o f)(x) = (2x + 3)² – 4(2x + 3) – 6

(g o f)(x) = 4x² + 12x + 9 – 8x – 12 – 6

(g o f)(x) = 4x² + 4x – 9