Diketahui y=5x+7m dan parabola y=xkuadrat +mx+11. nilai m?

By Admin ReiPosted on October 28, 2022

Diketahui y=5x+7m dan parabola y=xkuadrat +mx+11. nilai m?

$y_1=y_2$
$x^2+mx+11=5x+7m$
$x^2+mx+11-5x-7m=0$
$x^2+(m-5)x+(11-7m)=0$

berpotongan di dua titik, maka
$D>0$
$b^2-4ac>0$
$(m-5)^2-4(1)(11-7m)>0$
$m^2-10m+25-44+28m>0$
$m^2+18m-19>0$
$(m+19)(m-1)>0$
$m$ atau $m>1$