Persamaan garis yang melalui titik a (3,-2) dan tegak lurus garis 2x – 3y – 4=0

Jawaban:

2x – 3y – 12 = 0

Penjelasan dengan langkah-langkah:

A(3,-2) >> x1 = 3 dan y1 = -2

2x – 3y – 4 = 0 >> a = 2, b = -3, dan c = -4

gradien (m) = -a/b = -2/(-3) = 2/3

Persamaan :

y – y1 = m(x – x1)

y – (-2) = 2/3(x – 3)

y + 2 = 2/3(x – 3)

—————————- × 3

3y + 6 = 2x – 6

2x – 3y – 6 – 6 = 0

2x – 3y – 12 = 0