³log25 – ² log 20 – ²log2/5+ 5 log 625 dan sertakan Penjelasan Nya

Jawab:

Penjelasan dengan langkah-langkah:

logartima.

ᵃlog b + ᵃlog c = ᵃlog ( bc )

ᵃlog aᵇ = b

³log 25 – ²log 20 – ²log 2/5 + ⁵log 625

= ³log 5² – ( ²log 20 + ²2log 2/5 ) + ⁵log 5⁴

= 2³log 5 – { ²log ( 20 x 2/5 ) } + 4

= 2³log 5 – ( ²log 8 ) + 4

= 2³log 5 – ( ²log 2³ ) + 4

= 2³log 5 – ( 3 ) + 4

= 2³log 5 – 3 + 4

= 2³log 5 + 1

= 1 + 2³log 5

semoga bisa membantu

Logaritma

ⁿlog n = 1

•

³log 25 – ²log 20 -²log (2/5) + ⁵log 625

= ³log 5² – ²log (20 × 2/5) + ⁵log 5⁴

= 2 . ³log 5 – ²log 8 + 4 . ⁵log 5

= 2 . ³log 5 – ²log 2³ + 4

= 2 . ³log 5 – 3 + 4

= 1 + 2 ³log 5