Tolong beserta cara​

Limit Tak Tentu

.

misal x = t²

x= 1 –> t = 1

Lim (x -> 1 ) (3x + x√x – 4 ) / (x -1)

lim ( t -> 1) (3t² + t². t – 4 ) / (t² -1 )

lim ( t -> 1) (3t⁴ + t³ – 4 ) / (t² – 1)

lim (t -> 1) (t – 1)( 3t³ + 4t²+ 4t + 4) / (t – 1 )( t + 1 )

lim (t -> 1) ( 3t³ + 4t²+ 4t + 4) /( t + 1 )

t = 1 , L = (15)/(2)