1/3(2×+1)=1/4(3×-1) .nilai ×+2 adalah

Cara biasa
⅓(2x+1) = ¼(3x-1)
⅔x+⅓= ¾x-¼
⅔x-¾x = -¼-⅓
(8-9/ 12)x = -3-4 /12
-1/12x = -7/12
x = -7/12 x (-12)
x = 7

cara cepat
⅓(2x+1)= ¼(3x-1) kedua ruas kalikan 12
maka
12[⅓(2x+1)]= 12[¼(3x-1)]
4(2x+1) = 3(3x-1)
8x+4= 9x-3
8x-9x = -3-4
-x =-7
x=7

1/3 . (2x + 1) = 1/4 (3x – 1)
****ruas kiri dan kanan dikalikan 12****
4 (2x + 1) = 3 (3x – 1)
8x + 4 = 9x – 3
9x – 8x = 4 + 3
x = 7

maka,
nilai x + 2 = 7 + 2 = 9